WordPress如何获取自定义菜单名称和链接？其中有用到<?php wp_nav_menu(); ?>来互获取自定义菜单的内容。问题是总是获得只有<a href=\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\’\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\’>…</a>这样的输出格式。最后研究了下，得到了想要的结果。
<?php
$parameter = array(
\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\’theme_location\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\’ => \\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\’\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\’, //指定显示的导航名，如果没有设置，则显示第一个
\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\’menu\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\’ => \\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\’header-menu\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\’,
\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\’container\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\’ => \\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\’nav\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\’, //最外层容器标签名
\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\’container_class\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\’ => \\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\’primary\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\’, //最外层容器class名
\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\’container_id\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\’ => \\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\’\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\’, //最外层容器id值
\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\’menu_class\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\’ => \\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\’sf-menu\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\’, //ul标签class
\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\’menu_id\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\’ => \\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\’topnav\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\’, //ul标签id
\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\’echo\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\’ => true, //是否打印，默认是true，如果想将导航的代码作为赋值使用，可设置为false
\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\’fallback_cb\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\’ => \\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\’wp_page_menu\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\’, //备用的导航菜单函数，用于没有在后台设置导航时调用
\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\’before\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\’ => \\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\’\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\’, //显示在导航a标签之前
\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\’after\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\’ => \\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\’\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\’, //显示在导航a标签之后
\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\’link_before\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\’ => \\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\’\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\’, //显示在导航链接名之后
\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\’link_after\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\’ => \\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\’\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\’, //显示在导航链接名之前
\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\’items_wrap\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\’ => \\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\'<ul id=\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\”%1$s\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\”>%3$s</ul>\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\’,
\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\’depth\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\’ => 0, //显示的菜单层数，默认0，0是显示所有层
\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\’walker\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\’ => \\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\’\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\’ //调用一个对象定义显示导航菜单
);
wp_nav_menu($parameter);
?>
wordpress 中的自定义菜单函数 wp_nav_menu() 默认输出格式为：
<div>
<ul>
<li><a>菜单文字</a></li>
</ul>
</div>
百度了一圈还真没几个，可以完全解决的。有人这样做:
<?php
$parameter = array(
\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\’container\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\’ => \\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\’false\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\’,
\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\’items_wrap\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\’ => \\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\’%3$s\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\’,
);
wp_nav_menu($parameter);
?>
发现<li>标签还是无法去除。但是考虑下，如果加上 \\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\’echo\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\’ => false 输出带<li>的字符串，然后在用 strip_tags() 剥去其他标签，只保留<a>标签中的内容。就可以了。所以得到的完整代码如下。
<?php
$menuParameters = array(
\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\’container\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\’ => false,
\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\’echo\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\’ => false,
\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\’items_wrap\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\’ => \\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\’%3$s\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\’,
\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\’depth\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\’ => 0,
);
echo strip_tags(wp_nav_menu( $menuParameters ), \\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\'<a>\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\’ );
?>
输出结果如下图：